∫2[e^(x/2)+e^(-x/2)]dx
=4∫[e^(x/2)+e^(-x/2)]d(x/2)
令x/2=t
=4∫[e^(x/2)+e^(-x/2)]d(x/2)
=4∫[e^t+e^（-t)]dt
=4e^t-4e^(-t)+c
==4e^(x/2)-4e^(-x/2)+c
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∫2[e^(x/2)+e^(-x/2)]dx
=4∫[e^(x/2)+e^(-x/2)]d(x/2)
令x/2=t
=4∫[e^(x/2)+e^(-x/2)]d(x/2)
=4∫[e^t+e^（-t)]dt
=4e^t-4e^(-t)+c
==4e^(x/2)-4e^(-x/2)+c
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